Python Challenge - Level 2

Problem

recognize the characters. maybe they are in the book, but MAYBE they are in the page source.

Right click and select "View Page Source":

<!--
find rare characters in the mess below:
-->

<!--
%%[email protected]_$^__#)^)&!_+]!*@&^}@[@%]()%+$&[([email protected]%+%$*^@$^!+]!&_#)_*}{}}!}_]$[%}@[{[email protected]#_^{*
@##&{#&{&)*%(]{{([*}@[@&]+!!*{)!}{%+{))])[!^})+)$]#{*+^((@^@}$[**$&^{[email protected]#$%)[email protected](&
+^!{%_$&@^!}$_${)$_#)!({@!)(^}!*^&!$%_&&}&_#&@{)]{+)%*{&*%*&@%$+]!*__(#!*){%&@++
!_)^$&&%#+)}[email protected]!)&^}**#!_$([$!$}#*^}$+&#[{*{}{((#$]{[$[$$()_#}[email protected]}^@_&%^*!){*^^_$^
]@}#%[%!^[^_})[email protected]&}{@*!(@$%$^)}[_!}(*}#}#___}!](@_{{(*#%!%%+*)^+#%}$+_]#}%!**#!^_
...

Solution

Load Data

You can manually copy-and-paste the text to a file(resources/level2.txt in source code), then read from it:

>>> data = open('resources/level2.txt').read()

Read More

More about Python 3 - IO

Or extract the text from HTML directly. First load raw html source coding using urllib.request:

>>> import urllib.request
>>> html = urllib.request.urlopen("http://www.pythonchallenge.com/pc/def/ocr.html").read().decode()

Then extract the comment blocks in html. Note that by default dot does not match \n, so we need to use re .DOTALL flag.

>>> import re
>>> comments = re.findall("<!--(.*?)-->", html, re.DOTALL)

Alternatively we can use this:

>>> comments = re.findall("<!--([\w\n]*?)-->", html)

The pattern <!--(.*)--> will capture all blocks inside <!-- and -->. We only care about the last part, so

>>> data = comments[-1]

Find the Rare Characters

>>> count = {}
>>> for c in data:
...     count[c] = count.get(c, 0) + 1
... 
>>> count
{'*': 6034, '$': 6046, 'i': 1, '!': 6079, '[': 6108, 'u': 1, 'e': 1, '@': 6157, '#': 6115, 't': 1, '(': 6154, '+': 6066, '&': 6043, 'q': 1, 'l': 1, '%': 6104, '{': 6046, '}': 6105, 'a': 1, '^': 6030, ']': 6152, '\n': 1221, 'y': 1, '_': 6112, ')': 6186}

The rare characters only have 1 occurrence: t, i, u, e, l, y, q, a.

In the right order

If you are having a hard time to guess the meaning:

>>> import re
>>> "".join(re.findall("[A-Za-z]", data))
'equality'

Put Everything Together

import urllib.request
import re
html = urllib.request.urlopen("http://www.pythonchallenge.com/pc/def/ocr.html").read().decode()
data = re.findall("<!--(.*?)-->", html, re.DOTALL)[-1]
print("".join(re.findall("[A-Za-z]", data)))

result:

equality

Next Level

http://www.pythonchallenge.com/pc/def/equality.html

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